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    APPLICATION OF VECTORS




    Use of Vectors
    Most commonly in physics, vectors are used to represent displacement, velocity, and acceleration. Vectors are a combination of magnitude and direction, and are drawn as arrows. The length represents the magnitude and the direction of that quantity is the direction in which the vector is pointing.
     Scalar and Vector Quantities
    Difference between Scalar and Vector Quantities
    Distinguish between scalar and vector quantities
    Scalar Quantities
    These are physical quantities which have magnitude only. Examples of scalar quantities include mass, length, time, area, volume, density, distance, speed, electric current and specific heat capacity.

    Vector Quantities
    These are physical quantities which have both magnitude and direction. Examples of vector quantities include displacement, velocity, acceleration, force, pressure, retardation, and momentum.

    Addition of Vectors Using Graphical Method
    Add vectors using graphical method
    Scalar physical quantities have magnitude only. Thus, they can be added, multiplied, divided, or subtracted from each other.

    Example 1
    If you add a volume of 40cm3 of water to a volume of 60cmof water, then you will get 100cm3 of water.
    Vectors can be added, subtracted or multiplied conveniently with the help of a diagram.
    Vectors Representation
    A vector quantity can be represented on paper by a direct line segment.
    1. The length of the line segment represents the magnitude of a vector.
    2. The arrow head at the end represents the direction.
    Methods of Vector Addition
    There are two methods that are used to sum up two vectors:
    1. Triangle method
    2. Parallelogram method.
    Triangle Method
    A step-by-step method for applying the head-to-tail method to determine the sum of two or more vectors is given below.
    1.Choose a scale and indicate it on a sheet of paper. The best choice of scale is one that will result in a diagram that is as large as possible, yet fits on the sheet of paper.
    2.Pick a starting location and draw the first vectorto scalein the indicated direction. Label the magnitude and direction of the scale on the diagram (e.g., SCALE: 1 cm = 20 m).
    3.Starting from where the head of the first vector ends, draw the second vectorto scalein the indicated direction. Label the magnitude and direction of this vector on the diagram.
    4.Draw the resultant from the tail of the first vector to the head of the last vector. Label this vector as Resultantor simplyR.
    5. Using a ruler, measure the length of the resultant and determine its magnitude by converting to real units using the scale (4.4 cm x 20 m/1 cm = 88 m).
    6.Measure the direction of the resultant using the counterclockwise convention.
    Resultant vector: This is the vector drawn from the starting point of the first vector to the end point of the second vector which is the sum of two vectors.
    Where:
    • Vi - First vector
    • V2 - Second vector
    • R - Resultant vector
    Example 2
    Suppose a man walks starting from point A, a distance of 20m due North, and then 15m due East. Find his new position from A.
    Solution
    Use scale
    1CM Represents 5m
    Thus
    20m due to North Indicates 4 cm
    15m due to East Indicates 3cm.
    Demonstration
    The position of D is represented by Vector AD of magnitude 25M or 5CM at angle of 36051”
    Since
    • Tan Q = (Opposite /Adjacent)
    • Tan Q = 3cm /4cm
    • Q = Tan -1 (3/4)
    • Q = Tan -1(0.75)
    • Q = 35º51”
    The Resultant displacement is 25m ad direction Q = 36º51”
    The Triangle and Parallelogram Laws of Forces
    State the triangle and parallelogram laws of forces
    Triangle Law of Forces
    Triangle Law of Forces states that “If three forces are in equilibrium and two of the forces are represented in magnitude and direction by two sides of a triangle, then the third side of the triangle represents the third force called resultant force.”
    Example 3
    A block is pulled by a force of 4 N acting North wards and another force 3N acting North-East. Find resultant of these two forces.
    Demonstration
    Scale
    1Cm Represents 1N
    Draw a line AB of 4cm to the North. Then, starting from B, the top vectorofAB, draw a line BC of 3 CM at 45oEast of North.
    Join the line AC and measure the length (AC = 6.5 cm) which represents 6.5N. Hence, AC is the Resultant force of two forces 3N and 4N.
    Parallelogram Method
    In this method, the two Vectors are drawn (usually to scale) with a common starting point , If the lines representing the two vectors are made to be sides of s parallelogram, then the sum of the two vectors will be the diagonal of the parallelogram starting from the common point.
    The Parallelogram Law states that “If two vectors are represented by the two sides given and the inclined angle between them, then the resultant of the two vectors will be represented by the diagonal from their common point of parallelogram formed by the two vectors”.
    Example 4
    Two forces AB and AD of magnitude 40N and 60N respectively, are pulling a body on a horizontal table. If the two forces make an angle of 30o between them find the resultant force on the body.
    Solutiuon
    Choose a scale.
    1cm represents10N
    Draw a line AB of 4cm
    Draw a line AD of 6cm.
    Make an angle of 30between AB and AD. Complete the parallelogram ABCD using the two sides AB and include angle 30O.
    Draw the lineAC with a length of9.7 cm, which is equivalent to 97 N.
    The lineAC of the parallelogram ABCD represents the resultant force of AB and AD in magnitude and direction.
    Example 5
    Two ropes, one 3m long and the other and 6m long, are tied to the ceiling and their free ends are pulled by a force of 100N. Find the tension in each rope if they make an angle of 30o between them.
    Solution
    1cm represents 1N
    Thus
    3cm = represent 3m
    6cm = represents 6m
    Demonstration
    By using parallelogram method
    Tension, determined by parallelogram method, the length of diagonal using scale is 8.7 cm, which represents 100N force.
    Thus.
    Tension in 3m rope = 3 X 100 / 8.7 = 34.5N
    Tension in 6m rope = 6 x 100 / 8.7 =69N
    Tension force in 3m rope is 34.5N and in 6m rope is 69N.
    NoteEquilibrant forcesare those that act on a body at rest and counteract the force pushing or pulling the body in the opposite direction.